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How to pass a python dictionary as an argument into a function defined in LUA code? #269
Description
Hi,
I'm trying to pass a python dictionary as an argument into a function defined in LUA code but it crashes without exception.
The Lua function returns the first non-empty parameter, or nil if they are all empty.
LUA code: lua/Article.lua
local Article = { }
function validTextArg( args, name, ... )
local texte = args[name]
if type( texte ) == 'string' and texte ~= '' then
return texte
elseif #{ ... } > 0 then
return validTextArg( args, ... )
end
end
function Article.article( args )
-- validArg returns the first non-empty parameter, or nil if they are all empty.
-- Only parameter names should be passed to the function.
local validArg = function ( ... ) return validTextArg( args, ... ) or false end
return validArg( 'périodique', 'revue', 'journal' )
end
return ArticlePython code: main.py
import lupa.lua54 as lupa
lua = lupa.LuaRuntime(
unpack_returned_tuples=True,
register_eval=False,
)
print(
f"Using {lupa.LuaRuntime().lua_implementation} (compiled with {lupa.LUA_VERSION})"
)
lua.execute("""
local Article = require('lua/Article')
function Tpl_Article(args)
return Article.article(args)
end
"""
params = {
'revue': 'Revue des langues romanes',
'numéro': '105',
'année': '2001',
'pages': '503-517',
}
lua_result = lua.globals().Tpl_Article(params) # CrashHow do I invoke the LUA script and pass dictionary arguments ?
Activity
pHiney commentedon Aug 26, 2024
Do you need to use something like : args["revue"] in your lua function ???
https://pypi.org/project/lupa/#python-objects-in-lua
I'm just looking at lupa now for my project.